9x-3^2-3+x+4x^2+19=10x+7x^2+22

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Solution for 9x-3^2-3+x+4x^2+19=10x+7x^2+22 equation: 



9x-3^2-3+x+4x^2+19=10x+7x^2+22

We move all terms to the left:

9x-3^2-3+x+4x^2+19-(10x+7x^2+22)=0

We add all the numbers together, and all the variables

4x^2-(10x+7x^2+22)+10x+7=0

We get rid of parentheses

4x^2-7x^2-10x+10x-22+7=0

We add all the numbers together, and all the variables

-3x^2-15=0

a = -3; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·(-3)·(-15)
Δ = -180
Delta is less than zero, so there is no solution for the equation

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